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According to Graham's law, at a given te...

According to Graham's law, at a given temperature the ratio of diffusion `r_A/r_B` of gases A and B is given by
(where P and M are pressures and molecular weights of gases A and B respectively)

A

`(P_A/P_B)(M_A/M_B)^(1//2)`

B

`(M_A/M_B)(P_A/P_B)^(1//2)`

C

`(P_A/P_B)(M_B/M_A)^(1//2)`

D

`(M_A/M_B)(P_B/P_A)^(1//2)`

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To solve the question regarding Graham's law of diffusion, we can follow these steps: ### Step 1: Understand Graham's Law Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, this can be expressed as: \[ R \propto \frac{1}{\sqrt{D}} \] where \( R \) is the rate of diffusion and \( D \) is the density of the gas. ### Step 2: Relate Density to Pressure and Molecular Weight Density (\( D \)) of a gas can be related to its pressure (\( P \)) and molecular weight (\( M \)) using the ideal gas law: \[ D = \frac{PM}{RT} \] where \( R \) is the universal gas constant and \( T \) is the temperature in Kelvin. ### Step 3: Write the Ratios for Two Gases For two gases A and B, we can express their densities as: \[ D_A = \frac{P_A M_A}{RT} \quad \text{and} \quad D_B = \frac{P_B M_B}{RT} \] Now, substituting these into the expression for the rates of diffusion, we have: \[ R_A \propto \frac{1}{\sqrt{D_A}} \quad \text{and} \quad R_B \propto \frac{1}{\sqrt{D_B}} \] ### Step 4: Form the Ratio of Rates of Diffusion Taking the ratio of the rates of diffusion of gases A and B: \[ \frac{R_A}{R_B} = \frac{\sqrt{D_B}}{\sqrt{D_A}} \] ### Step 5: Substitute the Densities Substituting the expressions for \( D_A \) and \( D_B \): \[ \frac{R_A}{R_B} = \frac{\sqrt{\frac{P_B M_B}{RT}}}{\sqrt{\frac{P_A M_A}{RT}}} \] The \( RT \) cancels out: \[ \frac{R_A}{R_B} = \sqrt{\frac{P_B M_B}{P_A M_A}} \] ### Step 6: Final Expression Thus, we can express the final ratio of the rates of diffusion of gases A and B as: \[ \frac{R_A}{R_B} = \frac{P_B}{P_A} \cdot \sqrt{\frac{M_B}{M_A}} \] ### Summary The ratio of the rates of diffusion of gases A and B according to Graham's law is given by: \[ \frac{R_A}{R_B} = \frac{P_B}{P_A} \cdot \sqrt{\frac{M_B}{M_A}} \] ---

To solve the question regarding Graham's law of diffusion, we can follow these steps: ### Step 1: Understand Graham's Law Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, this can be expressed as: \[ R \propto \frac{1}{\sqrt{D}} \] where \( R \) is the rate of diffusion and \( D \) is the density of the gas. ...
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