Which of the following does not constitute 0.1g mole ?

Options

A. `6.022 xx 10^(22)` molecules of benzene
B. `0.14g " of " N_2` gas
C. `2.24 " litre of " CO_2` at S.T.P.
D. 0.40 g of He gas

Explanation

To solve the question "Which of the following does not constitute 0.1g mole?", we will analyze each option provided and calculate the number of moles for each substance.

### Step-by-Step Solution:

1. **Understanding the Concept of Moles**:
- A mole is a unit that measures the amount of substance. According to Avogadro's number, 1 mole of any substance contains \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.).

2. **Option 1: 6.022 × 10²² molecules of Benzene**:
- We know that 1 mole of benzene contains \(6.022 \times 10^{23}\) molecules.
- To find the number of moles in \(6.022 \times 10^{22}\) molecules:
\[ \text{Moles of Benzene} = \frac{6.022 \times 10^{22}}{6.022 \times 10^{23}} = 0.1 \text{ moles} \]

3. **Option 2: 0.14 grams of Nitrogen gas (N₂)**:
- The molar mass of nitrogen (N₂) is approximately 28 g/mol.
- To find the number of moles:
\[ \text{Moles of N₂} = \frac{0.14 \text{ g}}{28 \text{ g/mol}} = \frac{0.14}{28} = 0.005 \text{ moles} \]

4. **Option 3: 2.24 liters of CO₂**:
- At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters.
- To find the number of moles in 2.24 liters:
\[ \text{Moles of CO₂} = \frac{2.24 \text{ L}}{22.4 \text{ L/mol}} = 0.1 \text{ moles} \]

5. **Option 4: 0.4 grams of Helium gas (He)**:
- The molar mass of helium is approximately 4 g/mol.
- To find the number of moles:
\[ \text{Moles of He} = \frac{0.4 \text{ g}}{4 \text{ g/mol}} = 0.1 \text{ moles} \]

6. **Conclusion**:
- From the calculations:
- Option 1: 0.1 moles (Benzene)
- Option 2: 0.005 moles (Nitrogen)
- Option 3: 0.1 moles (CO₂)
- Option 4: 0.1 moles (Helium)
- The option that does not constitute 0.1g mole is **Option 2: 0.14 grams of Nitrogen gas (N₂)**.

### Final Answer:
**Option 2: 0.14 grams of Nitrogen gas (N₂)** does not constitute 0.1g mole.