A gas occupies 300.0 mL at `27^@C` and 730 mm pressure. What would be its volume at standard temperature and pressure (S.T.P.) ?

Answer

262.2 mL

Explanation

According to the gas equation, `(P_1V_1)/T_1 = (P_2V_2)/T_2`
In the present case,
`P_1 = 730 " mm Hg, " V_1 = 300.0 mL`,
`T_1 = 27 + 273 = 300 K`
`P_2 = 760 " mm Hg, " V_2 = ?, T_2 = 273 K` (at S.T.P.)
Substituting the values, we have
`(730 xx 300.0)/300 = (760 xxV_2)/273`
`:. " " V_2 = 262.2 mL`.