To determine whether the assertion and reason provided in the question are true or false, we will analyze both statements step by step.
### Step 1: Analyze the Assertion
**Assertion:** The alkaline earth metal hydroxides are more basic than the corresponding alkali metal hydroxides.
**Analysis:**
- Alkaline earth metals (Group 2) include elements like Be, Mg, Ca, Sr, and Ba.
- Alkali metals (Group 1) include elements like Li, Na, K, Rb, and Cs.
- The hydroxides of alkali metals (e.g., NaOH, KOH) are known to be strong bases and are more soluble in water compared to alkaline earth metal hydroxides (e.g., Ca(OH)₂, Sr(OH)₂).
- Generally, alkali metal hydroxides are more basic than alkaline earth metal hydroxides due to their higher solubility and the greater availability of hydroxide ions in solution.
**Conclusion for Assertion:** The assertion is **false**.
### Step 2: Analyze the Reason
**Reason:** The ionization enthalpies of alkaline earth metals are much lower than those of alkali metals.
**Analysis:**
- Ionization enthalpy refers to the energy required to remove an electron from an atom in the gaseous state.
- For alkali metals, the general electronic configuration is ns¹, while for alkaline earth metals, it is ns².
- Alkali metals have lower ionization enthalpies compared to alkaline earth metals because the removal of one electron from alkali metals leads to a stable noble gas configuration.
- In contrast, removing an electron from alkaline earth metals requires more energy because they have a more stable filled subshell (ns²).
**Conclusion for Reason:** The reason is also **false**.
### Final Conclusion
Both the assertion and the reason are false. Therefore, the correct answer to the question is **D** (Both Assertion and Reason are false).
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