The final products formed by ozonolysis of compound `R - CH = CR_2` is

Options

A. RCHO
B. `R_2CO`
C. both
D. none of these

Answer

To determine the final products formed by the ozonolysis of the compound \( R - CH = CR_2 \), we can follow these steps:

### Step 1: Identify the Structure
The compound given is \( R - CH = CR_2 \). Here, \( R \) represents a hydrocarbon group, and we have a double bond between the carbon atoms.

### Step 2: Understand Ozonolysis
Ozonolysis is a reaction where ozone (\( O_3 \)) cleaves double bonds in alkenes. In reductive ozonolysis, the double bond is broken, and ozone adds to the carbons involved in the double bond, forming carbonyl compounds.

### Step 3: Break the Double Bond
When we perform ozonolysis on the compound \( R - CH = CR_2 \), the double bond between \( CH \) and \( CR_2 \) will be cleaved. This results in the formation of two carbonyl groups.

### Step 4: Identify the Products
1. The carbon \( CH \) will form an aldehyde. The product from this carbon will be \( RCHO \) (an aldehyde).
2. The carbon \( CR_2 \) will form a ketone. The product from this carbon will be \( R_2C=O \) (a ketone).

### Step 5: Write the Final Products
Thus, the final products formed by the ozonolysis of the compound \( R - CH = CR_2 \) are:
- An aldehyde: \( RCHO \)
- A ketone: \( R_2C=O \)

### Conclusion
Both products, \( RCHO \) (an aldehyde) and \( R_2C=O \) (a ketone), are formed during the ozonolysis of the compound.

### Final Answer
The final products formed by ozonolysis of the compound \( R - CH = CR_2 \) are both an aldehyde \( RCHO \) and a ketone \( R_2C=O \).

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