To solve the question, we need to analyze the cell cycle and understand the DNA content at different phases. Here's the step-by-step solution:
### Step 1: Understand the Cell Cycle
The cell cycle consists of several phases: G1 (Gap 1), S (Synthesis), G2 (Gap 2), and M (Mitosis). Each phase has a specific role in cell growth and division.
### Step 2: Analyze DNA Content
- **G1 Phase**: The cell is in a growth phase where it prepares for DNA synthesis. At this stage, the DNA content is 2N (diploid).
- **S Phase**: This is the synthesis phase where DNA replication occurs. By the end of this phase, the DNA content doubles to 4N.
- **G2 Phase**: The cell continues to grow and prepares for mitosis, but the DNA content remains at 4N.
- **M Phase**: This phase includes prophase, metaphase, anaphase, and telophase, where the cell divides. The DNA content is still 4N during these stages.
### Step 3: Compare DNA Content in Different Phases
From the analysis:
- G1 Phase: 2N (half the DNA content compared to cells in S, G2, and M phases)
- S Phase: 4N (after DNA replication)
- G2 Phase: 4N (after DNA replication)
- M Phase (Prophase, Metaphase, Anaphase, Telophase): 4N
### Step 4: Identify the Correct Answer
The question states that the particular cell has half as much DNA as some of the other cells in a mitotically active tissue. Since cells in G1 phase have 2N DNA while cells in S, G2, and M phases have 4N, the correct answer is:
**C. G1 Phase**
### Final Answer
The cell in question could be in **G1 Phase**.
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