A seconds' pendulum is taken to a place where acceleration due to gravity falls to one-fourth. How is the time period of the pendulum affected, if at all ? Give reason. What will be its new time period ?

Explanation

To solve the problem, we need to analyze how the time period of a seconds pendulum changes when the acceleration due to gravity is reduced to one-fourth of its original value.

### Step-by-Step Solution:

1. **Understanding the Time Period Formula**:
The time period \( T \) of a simple pendulum is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g}}
...