Ocean waves of time period 10 s have wave velocity 15 `ms^(-1)`. Find the wavelength of these waves .
Text Solution
AI Generated Solution
To find the wavelength of ocean waves with a given time period and wave velocity, we can follow these steps:
### Step-by-Step Solution:
1. **Identify the given values**:
- Time period (T) = 10 seconds
- Wave velocity (V) = 15 m/s
...
Ocean waves of time period 10 s have wave velocity 15 ms^(-1) . Find : the horizontal distance between a wave crest and its adjoining wave trough.
S_(1) : The particles speed can never be equal to the wave speed in sine wave if the amplitude is less then wavelength divided by 2pi . S_(2) : In transverse wave of amplitude A, the maximum particle velocity is four times its wave velocity. Then, the wave length of the wave is piA S_(3) : the phase difference between two points separated by 1m in a wave of frequency 120 Hz is 90^(@) . the velocity of the wave is 480 m/s
A body of mass 10 mg is moving with a velocity of 100 ms^(-1) . The wavelength of the de Broglie wave associated with it would be
The figure shows the snapshot of a sound wave in a certain medium at a certain instant. If the velocity of the wave is 4 "ms"^(-1) , calculate the wavelength of the wave if its frequency is 20 Hz.
Derive an expression of wave velocity in terms of frequency and wavelength of the wave.
The separation between two consecutive crests in a transverse wave is 100 m. If wave velocity is 20 m s^(-1) , find the frequency of wave.
The separation between two consecutive crests in a transverse wave is 100 m. If wave velocity is 20 m s^(-1) , find the frequency of wave.
Ground wave have wavelength
Ground wave have wavelength
Simple harmonic wave is represented by the relation y (x, t) = a_(0) sin 2pi (vt - (x)/(lambda)) If the maximum particle velocity is three times the wave velocity, the wavelength lambda of the wave is
ICSE-PROPAGATION OF SOUND WAVES -EXERCISE -8(B) (Multiple choice type)