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12.825 gm of a sample of Ba(OH)(2) is di...

`12.825 gm` of a sample of `Ba(OH)_(2)` is dissolved in `10 ml` of `0.5 N HCl` solution. The excess of `HCl` was titrated with `0.2 N NaOH`. The volume of `NaOH` used was `10 c c`. The percentage of `Ba(OH)_(2)` in the sample is

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10 g of a sample of Ba(OH)_(2) is dissolved in 10 ml of 0.5 N HCl Solution : The excess of HCl was titrated with 0.2 N NaOH. The volume of NaOH used was 20 cc. Calculate the percentage of Ba(OH)_(2) in the sample.

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