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What sum of money lent at 6*5% per annum...

What sum of money lent at `6*5%` per annum will produce the same interest in 4 years as Rs. 7,500 produce in 6 years at 5% per annum ?

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To solve the problem step by step, we need to find the sum of money (let's call it P1) that, when lent at an interest rate of 6.5% per annum for 4 years, will yield the same interest as Rs. 7,500 at 5% per annum for 6 years. ### Step 1: Calculate the interest earned on Rs. 7,500 at 5% for 6 years. The formula for calculating simple interest (SI) is: \[ \text{SI} = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount - \( R \) = Rate of interest per annum - \( T \) = Time in years For this case: - \( P = 7500 \) - \( R = 5 \) - \( T = 6 \) Substituting the values: \[ \text{SI} = \frac{7500 \times 5 \times 6}{100} \] ### Step 2: Calculate the interest. Calculating the above expression: \[ \text{SI} = \frac{7500 \times 30}{100} = \frac{225000}{100} = 2250 \] So, the interest earned on Rs. 7,500 at 5% for 6 years is Rs. 2,250. ### Step 3: Set up the equation for the unknown principal (P1). Now, we need to find the principal amount (P1) that will yield the same interest of Rs. 2,250 at 6.5% for 4 years. Using the same formula for simple interest: \[ \text{SI} = \frac{P1 \times R1 \times T1}{100} \] Where: - \( P1 = x \) (the unknown principal we want to find) - \( R1 = 6.5 \) - \( T1 = 4 \) We know the interest is the same, so we can set up the equation: \[ 2250 = \frac{x \times 6.5 \times 4}{100} \] ### Step 4: Solve for P1. Rearranging the equation to solve for \( x \): \[ 2250 = \frac{x \times 26}{100} \] Multiplying both sides by 100: \[ 225000 = 26x \] Now, divide both sides by 26: \[ x = \frac{225000}{26} \approx 8653.846 \] ### Step 5: Round the answer. Rounding off to two decimal places, we get: \[ x \approx 8653.85 \] Thus, the sum of money that needs to be lent at 6.5% per annum to produce the same interest in 4 years as Rs. 7,500 produces in 6 years at 5% per annum is approximately Rs. 8,653.85. ### Summary of the Solution: The principal amount (P1) is Rs. 8,653.85. ---
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