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The dimensions of a class- room are len...

The dimensions of a class- room are length = 15 m. breadth =12m and height 7.5 m Find . How many children can be accommodated in this class - room assuming ` 3.6m ^(3)` of air is needed for each child.

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To find out how many children can be accommodated in the classroom, we need to follow these steps: ### Step 1: Calculate the volume of the classroom. The formula for the volume \( V \) of a rectangular prism (classroom) is given by: \[ V = \text{length} \times \text{breadth} \times \text{height} \] Given: - Length = 15 m - Breadth = 12 m - Height = 7.5 m Substituting the values: \[ V = 15 \, \text{m} \times 12 \, \text{m} \times 7.5 \, \text{m} \] ### Step 2: Perform the multiplication. First, calculate \( 12 \times 7.5 \): \[ 12 \times 7.5 = 90 \, \text{m}^2 \] Now, multiply this result by the length: \[ V = 15 \, \text{m} \times 90 \, \text{m}^2 = 1350 \, \text{m}^3 \] ### Step 3: Determine the volume of air required per child. It is given that each child requires \( 3.6 \, \text{m}^3 \) of air. ### Step 4: Calculate the number of children that can be accommodated. To find the number of children \( N \), we divide the total volume of the classroom by the volume required per child: \[ N = \frac{\text{Total Volume}}{\text{Volume per child}} = \frac{1350 \, \text{m}^3}{3.6 \, \text{m}^3} \] ### Step 5: Perform the division. Calculating the division: \[ N = \frac{1350}{3.6} \] To simplify, we can multiply both the numerator and the denominator by 10 to eliminate the decimal: \[ N = \frac{13500}{36} \] Now, divide \( 13500 \) by \( 36 \): \[ N = 375 \] ### Final Answer: Thus, the number of children that can be accommodated in the classroom is **375**. ---
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