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A sum of money is invested at 10% per annum compounded half-yearly. If the difference of amounts at the end of 6 months and 12 months is Rs 189, find the sum of money invested,

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To solve the problem step by step, we will follow the formula for compound interest and apply it to find the sum of money invested. ### Step-by-Step Solution: 1. **Identify the Variables**: - Let the sum of money invested be \( P \) (in rupees). - The rate of interest is \( 10\% \) per annum. - The interest is compounded half-yearly. 2. **Calculate the Amount after 6 Months**: - The formula for compound interest is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] - Here, \( r = 10\% = 10 \), \( n = 2 \) (since it's compounded half-yearly), and \( t = \frac{1}{2} \) (for 6 months). - Substitute the values into the formula: \[ A_{6\text{ months}} = P \left(1 + \frac{10}{2 \times 100}\right)^{2 \times \frac{1}{2}} = P \left(1 + \frac{10}{200}\right)^{1} = P \left(1 + 0.05\right) = P \times 1.05 \] - Therefore, the amount after 6 months is: \[ A_{6\text{ months}} = 1.05P \] 3. **Calculate the Amount after 12 Months**: - Now, for 12 months, \( t = 1 \) year. - Substitute the values into the formula: \[ A_{12\text{ months}} = P \left(1 + \frac{10}{2 \times 100}\right)^{2 \times 1} = P \left(1 + 0.05\right)^{2} = P \left(1.05\right)^{2} \] - Calculate \( (1.05)^{2} \): \[ (1.05)^{2} = 1.1025 \] - Therefore, the amount after 12 months is: \[ A_{12\text{ months}} = 1.1025P \] 4. **Set Up the Equation for the Difference**: - According to the problem, the difference between the amounts at the end of 6 months and 12 months is Rs 189: \[ A_{12\text{ months}} - A_{6\text{ months}} = 189 \] - Substitute the amounts: \[ 1.1025P - 1.05P = 189 \] - Simplify the equation: \[ (1.1025 - 1.05)P = 189 \] \[ 0.0525P = 189 \] 5. **Solve for \( P \)**: - Divide both sides by \( 0.0525 \): \[ P = \frac{189}{0.0525} \] - Calculate \( P \): \[ P = 3600 \] 6. **Conclusion**: - The sum of money invested is Rs 3600. ### Final Answer: The sum of money invested is Rs 3600. ---
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ICSE-COMPOUND INTEREST (USING FORMULA)-EXERCISE 3(E)
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  8. Nikita invests Rs 6,000 for two years at a certain rate of interest co...

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  9. Simple interest on a sum of money for 2 years at 4% growth rate is Rs ...

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  10. Find the compound interest to the nearest rupee on Rs 10,800 for 2(1)/...

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  12. The value of a machine, purchased two years ago, depreciates at the an...

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  13. Anuj and Rajesh each lent the same sum of money for 2 years at 8% simp...

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  14. Calculate the sum of money on which the compound interest (payable ann...

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  15. A sum of money was invested for 3 years, interest being compounded ann...

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  16. A sum of money is invested at 10% per annum compounded half-yearly. If...

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  17. Rohit borrows Rs 86,000 from Arun for two years at 5% per annum simple...

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  18. The simple interest on a certain sum of money for 3 years at 5% per an...

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  19. Nikita invests Rs 6,000 for two years at a certain rate of interest co...

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  20. Nikita invests Rs 6,000 for two years at a certain rate of interest co...

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