If `sqrt(3)=1*732`, find (correct to two decimal places) the value of the following `sin60^(@)`

Answer

To find the value of \( \sin 60^\circ \) given that \( \sqrt{3} = 1.732 \), we can follow these steps:

### Step 1: Recall the trigonometric ratio
We know from trigonometric ratios that:
\[ \sin 60^\circ = \frac{\sqrt{3}}{2} \]

### Step 2: Substitute the value of \( \sqrt{3} \)
Now, substitute the given value of \( \sqrt{3} \) into the equation:
\[ \sin 60^\circ = \frac{1.732}{2} \]

### Step 3: Perform the division
Now, calculate \( \frac{1.732}{2} \):
\[ \sin 60^\circ = 0.866 \]

### Step 4: Round to two decimal places
Since the question asks for the value correct to two decimal places, we round \( 0.866 \):
\[ \sin 60^\circ \approx 0.87 \]

### Final Answer
Thus, the value of \( \sin 60^\circ \) correct to two decimal places is:
\[ \sin 60^\circ \approx 0.87 \]

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