Home
Class 9
MATHS
Solve for x : sin(x+10^(@))=1/2...

Solve for x :
`sin(x+10^(@))=1/2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( \sin(x + 10^\circ) = \frac{1}{2} \), we can follow these steps: ### Step 1: Identify the angle whose sine is \( \frac{1}{2} \) We know that: \[ \sin(30^\circ) = \frac{1}{2} \] Thus, we can set up the equation: \[ x + 10^\circ = 30^\circ \] ### Step 2: Solve for \( x \) Now, we will isolate \( x \) by subtracting \( 10^\circ \) from both sides: \[ x = 30^\circ - 10^\circ \] \[ x = 20^\circ \] ### Step 3: Consider the general solution The sine function is periodic, and it has a periodicity of \( 360^\circ \). Therefore, we also need to consider the second angle where sine is \( \frac{1}{2} \): \[ x + 10^\circ = 180^\circ - 30^\circ \] This gives us: \[ x + 10^\circ = 150^\circ \] Now, solving for \( x \): \[ x = 150^\circ - 10^\circ \] \[ x = 140^\circ \] ### Final Solutions Thus, the solutions for \( x \) are: \[ x = 20^\circ \quad \text{and} \quad x = 140^\circ \]
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRICAL RATIOS OF STANDARD ANGLES

    ICSE|Exercise EXERCISE 23(B)|34 Videos
  • TRIGONOMETRICAL RATIOS

    ICSE|Exercise EXERCISE 22(B)|50 Videos
  • TRIGONOMETRY

    ICSE|Exercise TOPIC -4 ( COMPLEMENTARY ANGLES ) (4 MARKS QUESTIONS )|4 Videos

Similar Questions

Explore conceptually related problems

Solve for x: sin(2 tan^(-1)x)=1

Solve for x : cos(2sin^(-1)x)=1/3

Solve for x: √3 sin x + cosx = 1

Solve for x : sin^(2)x+sin^(2)30^(@)=1

Solve for x : sin^(- 1)(sin((2x^2+4)/(1+x^2)))lt pi-3

Solve for x : cos^(2)30^(@)+sin^(2)2x=1

Solve for x: sin^(-1)(1-x)-2sin^(-1)x=pi/2

Solve for x, sin^(2)(x)/(2)=sin x cos x -1/2

Solve for x : (i) cos((x)/(2) + 10^(@)) = (sqrt(3))/(2) (ii) sin^(2) 60^(@) + cos^(2)(3x - 9^(@)) = 1

Solve for x:log_(2)(sin""(x)/(2))lt-1