Evaluate :
`14 sin 30^(@)+6cos 60^(@)-5tan 45^(@)`

Answer

To solve the expression \( 14 \sin 30^\circ + 6 \cos 60^\circ - 5 \tan 45^\circ \), we will evaluate each trigonometric function step by step.

### Step 1: Evaluate \( \sin 30^\circ \)
We know that:
\[ \sin 30^\circ = \frac{1}{2} \]

### Step 2: Substitute \( \sin 30^\circ \) into the expression
Now substitute \( \sin 30^\circ \) into the expression:
\[ 14 \sin 30^\circ = 14 \times \frac{1}{2} = 7 \]

### Step 3: Evaluate \( \cos 60^\circ \)
Next, we evaluate:
\[ \cos 60^\circ = \frac{1}{2} \]

### Step 4: Substitute \( \cos 60^\circ \) into the expression
Now substitute \( \cos 60^\circ \) into the expression:
\[ 6 \cos 60^\circ = 6 \times \frac{1}{2} = 3 \]

### Step 5: Evaluate \( \tan 45^\circ \)
We know that:
\[ \tan 45^\circ = 1 \]

### Step 6: Substitute \( \tan 45^\circ \) into the expression
Now substitute \( \tan 45^\circ \) into the expression:
\[ 5 \tan 45^\circ = 5 \times 1 = 5 \]

### Step 7: Combine all parts of the expression
Now we combine all the evaluated parts:
\[ 14 \sin 30^\circ + 6 \cos 60^\circ - 5 \tan 45^\circ = 7 + 3 - 5 \]

### Step 8: Simplify the expression
Now simplify:
\[ 7 + 3 = 10 \]
\[ 10 - 5 = 5 \]

### Final Answer
Thus, the final answer is:
\[ \boxed{5} \]