Find the quadratic equation whose solution set is `{-2, 3}`.

Answer

To find the quadratic equation whose solution set is \(\{-2, 3\}\), we can follow these steps:

### Step 1: Identify the roots
The roots of the quadratic equation are given as \(x = -2\) and \(x = 3\).

### Step 2: Write the factors
Using the roots, we can express the quadratic equation in its factored form:
\[ (x + 2)(x - 3) = 0 \]

### Step 3: Expand the factors
Now, we will expand the expression:
\[ (x + 2)(x - 3) = x^2 - 3x + 2x - 6 \]

### Step 4: Combine like terms
Combine the like terms:
\[ x^2 - 3x + 2x - 6 = x^2 - x - 6 \]

### Step 5: Write the final equation
Thus, the quadratic equation is:
\[ x^2 - x - 6 = 0 \]

### Final Answer
The required quadratic equation is:
\[ x^2 - x - 6 = 0 \]

---