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A sum of 700 is to be paid to give seven...

A sum of 700 is to be paid to give seven cash prizes to the students of a school for their overall academic performance. If the cost of each prize is 20 less than its preceding prize, find the value of each of the prizes.

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To solve the problem step by step, we will use the concept of Arithmetic Progression (AP). ### Step 1: Define the first prize Let the value of the first prize be \( A \). ### Step 2: Define the subsequent prizes According to the problem, each subsequent prize is 20 less than the preceding one. Therefore, the prizes can be expressed as: - First prize: \( A \) - Second prize: \( A - 20 \) - Third prize: \( A - 40 \) - Fourth prize: \( A - 60 \) - Fifth prize: \( A - 80 \) - Sixth prize: \( A - 100 \) - Seventh prize: \( A - 120 \) ### Step 3: Write the sum of the prizes The total sum of the prizes is given as 700. Therefore, we can write the equation for the sum of the prizes: \[ A + (A - 20) + (A - 40) + (A - 60) + (A - 80) + (A - 100) + (A - 120) = 700 \] ### Step 4: Simplify the equation Combining like terms, we have: \[ 7A - (20 + 40 + 60 + 80 + 100 + 120) = 700 \] Calculating the sum of the constants: \[ 20 + 40 + 60 + 80 + 100 + 120 = 420 \] So, the equation becomes: \[ 7A - 420 = 700 \] ### Step 5: Solve for \( A \) Now, we can isolate \( A \): \[ 7A = 700 + 420 \] \[ 7A = 1120 \] \[ A = \frac{1120}{7} = 160 \] ### Step 6: Calculate the values of all prizes Now that we have \( A = 160 \), we can find the values of all the prizes: - First prize: \( 160 \) - Second prize: \( 160 - 20 = 140 \) - Third prize: \( 160 - 40 = 120 \) - Fourth prize: \( 160 - 60 = 100 \) - Fifth prize: \( 160 - 80 = 80 \) - Sixth prize: \( 160 - 100 = 60 \) - Seventh prize: \( 160 - 120 = 40 \) ### Final Values of the Prizes The values of the seven prizes are: - \( 160, 140, 120, 100, 80, 60, 40 \)
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