Home
Class 10
MATHS
Find the next two terms of the series : ...

Find the next two terms of the series :
`2-6+18-54 . . . . . . . . . . . . .`

Text Solution

AI Generated Solution

The correct Answer is:
To find the next two terms of the series \(2, -6, 18, -54, \ldots\), we can follow these steps: ### Step 1: Identify the first term and the common ratio The first term of the series is: \[ a_1 = 2 \] The second term is: \[ a_2 = -6 \] To find the common ratio \(r\), we can calculate: \[ r = \frac{a_2}{a_1} = \frac{-6}{2} = -3 \] ### Step 2: Verify the common ratio with the next terms Now, let's verify the common ratio with the next terms: - For \(a_3\): \[ r = \frac{a_3}{a_2} = \frac{18}{-6} = -3 \] - For \(a_4\): \[ r = \frac{a_4}{a_3} = \frac{-54}{18} = -3 \] Since the common ratio \(r\) is consistently \(-3\) for all terms, we confirm that this series is a geometric progression (GP) with: \[ a = 2 \quad \text{and} \quad r = -3 \] ### Step 3: Find the next two terms To find the next terms \(a_5\) and \(a_6\), we can use the formula for the \(n\)-th term of a geometric progression: \[ a_n = a \cdot r^{n-1} \] #### Finding \(a_5\): \[ a_5 = a \cdot r^{5-1} = 2 \cdot (-3)^4 \] Calculating \((-3)^4\): \[ (-3)^4 = 81 \] Thus, \[ a_5 = 2 \cdot 81 = 162 \] #### Finding \(a_6\): \[ a_6 = a \cdot r^{6-1} = 2 \cdot (-3)^5 \] Calculating \((-3)^5\): \[ (-3)^5 = -243 \] Thus, \[ a_6 = 2 \cdot (-243) = -486 \] ### Final Answer The next two terms of the series are: \[ 162, -486 \]
Promotional Banner

Topper's Solved these Questions

  • GEOMETRIC PROGRESSION

    ICSE|Exercise Exercise 11(B) |10 Videos
  • GEOMETRIC PROGRESSION

    ICSE|Exercise Exercise 11(C) |10 Videos
  • GEOMETRIC PROGRESSION

    ICSE|Exercise Exercise 11(D) |26 Videos
  • FACTORISATION

    ICSE|Exercise M.C.Q(Competency Based Questions )|15 Videos
  • GOODS AND SERVICE TEX (GST)

    ICSE|Exercise Competency Based Questions |20 Videos

Similar Questions

Explore conceptually related problems

Find the sum of 6 terms of the series 2+6+18+…..

Find the nth term of the series 1+5+18+58+179+"..." .

Find the 15^(th) term of the series 3 - 6 +9 - 12 + …

Find the 6th term of the progression 2, 6, 18,….

Find the sum to 10 terms oif the series 1+3+6+10+…..

Find the sum of the G.P. : 2+6+18+54+ . . . . . . . .. +4374 .

Find the next three terms of the series : (2)/(27),(2)/(9),(2)/(3), . . . . . . . . . . .

How many terms of the series 2+6+18+ . . . . . . . . . . . Must be taken to make the sum equal to 728 ?

Find the sum of 7 terms of the series 2+0.2+0.02+….

Find the sum of the series 2+6+18++4374