Fill in the blanks :
`{:("Point","Transformation ","Image"),(.........., "Reflection in y - axis",(0,6)):}`

Answer

To solve the problem, we need to find the original point \( P \) whose reflection in the y-axis is given as \( P' (0, 6) \).

### Step-by-step Solution:

1. **Understanding Reflection in the Y-axis**:
- When a point \( P(x, y) \) is reflected in the y-axis, its x-coordinate changes sign while the y-coordinate remains the same. Thus, the reflection of point \( P \) will be \( P'(-x, y) \).

2. **Identify the Coordinates of the Image**:
- We know that the image point \( P' \) is given as \( (0, 6) \).

3. **Set Up the Reflection Equation**:
- According to the reflection property, if \( P' \) is \( (0, 6) \), then the original point \( P \) must satisfy:
\[ P' = (-x, y) \implies (0, 6) = (-x, y) \]

4. **Solve for the Coordinates of Point \( P \)**:
- From the equation \( (0, 6) = (-x, y) \), we can equate the coordinates:
- For the x-coordinate:
\[ -x = 0 \implies x = 0 \]
- For the y-coordinate:
\[ y = 6 \]

5. **Conclusion**:
- Therefore, the coordinates of point \( P \) are \( (0, 6) \).

### Final Answer:
The required point \( P \) is \( (0, 6) \).

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