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The point P(x, y) is first reflected in ...

The point P(x, y) is first reflected in the x-axis and then reflected in the origin to P'. If P' has co-ordinates (-8, 5), evaluate x and y.

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To solve the problem, we will follow the steps of reflecting the point \( P(x, y) \) first in the x-axis and then in the origin to find the coordinates of \( P' \) and evaluate \( x \) and \( y \). ### Step-by-Step Solution: 1. **Reflect Point P in the x-axis**: - The reflection of a point \( P(x, y) \) in the x-axis results in the point \( P_1(x, -y) \). - This means the y-coordinate changes sign while the x-coordinate remains the same. 2. **Reflect Point P_1 in the Origin**: - The reflection of a point \( P_1(x, -y) \) in the origin results in the point \( P'(-x, y) \). - Here, both the x and y coordinates change their signs. 3. **Given Coordinates of P'**: - We are given that \( P' \) has coordinates \( (-8, 5) \). - Therefore, we can set up the equations based on the reflection process: \[ -x = -8 \quad \text{(1)} \] \[ y = 5 \quad \text{(2)} \] 4. **Solve for x**: - From equation (1): \[ -x = -8 \implies x = 8 \] 5. **Solve for y**: - From equation (2): \[ y = 5 \] 6. **Final Values**: - Thus, the values of \( x \) and \( y \) are: \[ x = 8, \quad y = 5 \] ### Summary: The coordinates of point \( P \) are \( (8, 5) \).
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