In parallelogram ABCD, side AB is greater than side BC and P is a point in AC such that PB bisects angle B.
Prove that P is equidistant from AB and BC.

In a triangle ABC, side AC is greater than side AB and point D lies on side BC such that AD bisects angle BAC. Show that: angle ADB is acute.

In parallelogram ABCD, the bisector of angle A meets DC at P and AB= 2AD. Prove that: BP bisects angle B

In a parallelogram ABCD, P is a point on side AD such that 3AP = AD and Q is a point on BC such that 3CQ = BC. Prove that : AQCP is a parallelogram.

In Delta ABC, AB =AC and D is a piont in side BC such that AD bisect angle BAC. Show that AD is perpendicular bisector of side BC.

The locus of a point on rhombus ABCD, so that it is equidistant from AB and BC

In the parallelogram ABCD , the side AB is produced to the point X.so that BX= AB. The line DX cuts BC at E. Prove that : DBXC is a parallelogram.

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that CE bisects angle C

Construct a triangle ABC which angle ABC=75^(@), AB=5" cm"and BC =6.4" cm" . Draw perpendicular bisector of side BC and also the bisector of angle ACB. If these bisector intersect each other at point P, prove that P is equidistant from B and C, and also from AC and BC.

In parallelogram ABCD, P is a point on side AB and Q is a ponit on side BC. Prove that : (i) DeltaCPD and DeltaAQD are equal in area. (ii) Area (DeltaAQD) = "Area" (DeltaAPD)+ "Area" (DeltaCPB)

In parallelogram ABCD, P is a point on side AB and Q is a ponit on side BC. Prove that : (i) DeltaCPD and DeltaAQD are equal in area. (ii) Area (DeltaAQD) = "Area" (DeltaAPD)+ "Area" (DeltaCPB)