On a graph paper, draw the line `x=6`. Now, on the same graph paper, draw the locus of the point which moves in such a way that its distance from the given line is always equal to 3 units.

Answer

### Step-by-Step Solution:

1. **Draw the Axes**: Start by drawing the x-axis and y-axis on a graph paper. Label them as \(x\) and \(y\).

**Hint**: Make sure to mark equal intervals on both axes for accurate representation.

2. **Draw the Line \(x = 6\)**: Draw a vertical line parallel to the y-axis at \(x = 6\). This line represents all points where the x-coordinate is 6.

**Hint**: Use a ruler to ensure that the line is straight and extends sufficiently in both directions.

3. **Determine the Distance**: Since the locus of the point must be 3 units away from the line \(x = 6\), identify the two lines that are 3 units away from this line. These will be at \(x = 6 - 3 = 3\) and \(x = 6 + 3 = 9\).

**Hint**: Remember that moving left or right from the line gives you the new x-coordinates.

4. **Draw the Lines \(x = 3\) and \(x = 9\)**: Draw two vertical lines parallel to the y-axis at \(x = 3\) and \(x = 9\). These lines represent all points that are 3 units away from the line \(x = 6\).

**Hint**: Again, use a ruler to keep the lines straight and label them clearly.

5. **Label the Locus**: The locus of points that are always 3 units away from the line \(x = 6\) is represented by the lines \(x = 3\) and \(x = 9\).

**Hint**: Clearly indicate that the locus consists of both lines for clarity.

### Final Answer:
The locus of the point which moves in such a way that its distance from the line \(x = 6\) is always equal to 3 units is given by the lines \(x = 3\) and \(x = 9\).