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The radius of the base and the height of a right circular cone are 7 cm and 24 cm respectively. Find the volume and the total surface area of the cone.

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To find the volume and total surface area of a right circular cone with a radius of 7 cm and a height of 24 cm, we can follow these steps: ### Step 1: Calculate the Volume of the Cone The formula for the volume \( V \) of a cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] Where: - \( r \) is the radius of the base of the cone - \( h \) is the height of the cone Substituting the values: \[ V = \frac{1}{3} \times \frac{22}{7} \times (7)^2 \times (24) \] ### Step 2: Simplify the Volume Calculation Calculating \( (7)^2 \): \[ (7)^2 = 49 \] Now substituting back into the volume formula: \[ V = \frac{1}{3} \times \frac{22}{7} \times 49 \times 24 \] ### Step 3: Cancel and Calculate We can cancel \( 49 \) with \( 7 \): \[ 49 \div 7 = 7 \] So now we have: \[ V = \frac{1}{3} \times 22 \times 7 \times 24 \] Next, simplify \( 24 \div 3 \): \[ 24 \div 3 = 8 \] Now substituting: \[ V = 22 \times 7 \times 8 \] ### Step 4: Final Calculation for Volume Calculating \( 22 \times 7 \): \[ 22 \times 7 = 154 \] Now multiply by \( 8 \): \[ 154 \times 8 = 1232 \] Thus, the volume of the cone is: \[ V = 1232 \, \text{cm}^3 \] ### Step 5: Calculate the Slant Height The slant height \( l \) of the cone can be calculated using the Pythagorean theorem: \[ l = \sqrt{h^2 + r^2} \] Substituting the values: \[ l = \sqrt{(24)^2 + (7)^2} \] Calculating \( (24)^2 \) and \( (7)^2 \): \[ (24)^2 = 576, \quad (7)^2 = 49 \] Now substituting back: \[ l = \sqrt{576 + 49} = \sqrt{625} \] Calculating the square root: \[ l = 25 \, \text{cm} \] ### Step 6: Calculate the Total Surface Area The formula for the total surface area \( A \) of a cone is: \[ A = \pi r l + \pi r^2 \] Substituting the values: \[ A = \frac{22}{7} \times 7 \times 25 + \frac{22}{7} \times (7)^2 \] ### Step 7: Simplify the Surface Area Calculation First term: \[ A = \frac{22}{7} \times 7 \times 25 = 22 \times 25 = 550 \] Second term: \[ A = \frac{22}{7} \times 49 = 22 \times 7 = 154 \] ### Step 8: Final Calculation for Total Surface Area Now combine both terms: \[ A = 550 + 154 = 704 \, \text{cm}^2 \] ### Final Answers - Volume of the cone: \( 1232 \, \text{cm}^3 \) - Total surface area of the cone: \( 704 \, \text{cm}^2 \)
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ICSE-CYLINDER, CONE AND SPHERE -EXERCISE 20 (G)
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  2. What is the least number of solid metallic spheres, each of 6 cm diame...

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  3. A largest sphere is to be carved out of a right circular cylinder of r...

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  4. A right circular cylinder having diameter 12 cm and height 15 cm is ...

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  5. A solid is in the form of a cone standing on a hemi-sphere with both t...

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  6. The diameter of a sphere is 6 cm. It is melted and drawn into a wire o...

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  7. What is the ratio of the volume of a cube to that of a sphere which...

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  8. A solid iron pole having cylindrical portion 110cm high and of base ...

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  9. In the following diagram a rectangular platform with a semi-circular e...

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  10. The cross-section of a tunnel is a square of side 7 m surmounted by a ...

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  11. The cross-section of a tunnel is a square of side 7 m surmounted by a ...

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  12. The cross-section of a tunnel is a square of side 7 m surmounted by a ...

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  13. A cylindrical water tank of diameter 2.8 m and height 4.2 m is being f...

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  14. Water flows, at 9 km per hour, through a cylindrical pipe of cross-sec...

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  15. The given figure shows the cross-section of a cone, a cylinder and a h...

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  16. A solid consisting of a right circular cone, standing on a hemisphere,...

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  17. A metal container in the form of a cylinder is surmounted by a hemisph...

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  18. A metal container in the form of a cylinder is surmounted by a hemisph...

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  19. An exhibition tent is in the form of a cylinder surmounted by a cone. ...

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  20. A test tube consists of a hemisphere and a cylinder of the same radius...

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  21. A solid is in the form of a right circular cone mounted on a hemispher...

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