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The total surface area of a hollow cylin...

The total surface area of a hollow cylinder, which is open from both the sides, is 3575 cm", area of its base ring is `357.5 cm^(2)` and its height is 14 cm. Find the thickness of the cylinder.

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To solve the problem of finding the thickness of a hollow cylinder, we will follow these steps: ### Step 1: Understand the Given Information We are given: - Total Surface Area (TSA) of the hollow cylinder = 3575 cm² - Area of the base ring = 357.5 cm² - Height (h) of the cylinder = 14 cm ### Step 2: Set Up the Equations 1. The area of the base ring can be expressed as: \[ \text{Area of base ring} = \pi (R^2 - r^2) = 357.5 \text{ cm}^2 \] where \( R \) is the outer radius and \( r \) is the inner radius. 2. The total surface area of the hollow cylinder (open from both sides) is given by: \[ \text{TSA} = 2\pi Rh + 2\pi rh + \text{Area of base ring} \] Since the cylinder is open from both sides, we can simplify it to: \[ \text{TSA} = 2\pi h(R + r) + \pi (R^2 - r^2) \] Setting this equal to the given TSA: \[ 3575 = 2\pi h(R + r) + 357.5 \] ### Step 3: Substitute Known Values Substituting \( h = 14 \) cm and rearranging the equation: \[ 3575 - 357.5 = 2\pi(14)(R + r) \] \[ 3217.5 = 28\pi(R + r) \] ### Step 4: Calculate \( R + r \) Now, we can solve for \( R + r \): \[ R + r = \frac{3217.5}{28\pi} \] Using \( \pi \approx \frac{22}{7} \): \[ R + r = \frac{3217.5 \times 7}{28 \times 22} = \frac{22522.5}{616} \approx 36.5 \text{ cm} \] ### Step 5: Solve for \( R^2 - r^2 \) From the area of the base ring: \[ R^2 - r^2 = \frac{357.5 \times 7}{22} = \frac{2502.5}{22} \approx 113.75 \text{ cm}^2 \] ### Step 6: Use the Two Equations Now we have two equations: 1. \( R + r = 36.5 \) 2. \( R^2 - r^2 = 113.75 \) We can express \( R \) in terms of \( r \): \[ R = 36.5 - r \] Substituting into the second equation: \[ (36.5 - r)^2 - r^2 = 113.75 \] Expanding and simplifying: \[ 1332.25 - 73r + r^2 - r^2 = 113.75 \] \[ 1332.25 - 73r = 113.75 \] \[ 73r = 1218.5 \] \[ r = \frac{1218.5}{73} \approx 16.7 \text{ cm} \] ### Step 7: Find \( R \) Now substituting back to find \( R \): \[ R = 36.5 - 16.7 \approx 19.8 \text{ cm} \] ### Step 8: Find the Thickness The thickness \( t \) of the cylinder is given by: \[ t = R - r = 19.8 - 16.7 \approx 3.1 \text{ cm} \] ### Final Answer The thickness of the hollow cylinder is approximately **3.1 cm**. ---
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ICSE-CYLINDER, CONE AND SPHERE -EXERCISE 20 (A)
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