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Two right circular solid cylinders have ...

Two right circular solid cylinders have radii in the ratio 3 : 5 and heights in the ratio 2:3. Find the ratio between their curved surface areas.

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To solve the problem of finding the ratio between the curved surface areas of two right circular solid cylinders with given ratios of radii and heights, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Ratios**: - The ratio of the radii of the two cylinders is given as \( r_1 : r_2 = 3 : 5 \). - The ratio of the heights of the two cylinders is given as \( h_1 : h_2 = 2 : 3 \). 2. **Formula for Curved Surface Area**: - The formula for the curved surface area (CSA) of a cylinder is given by: \[ \text{CSA} = 2 \pi r h \] - Therefore, the curved surface areas of the two cylinders can be expressed as: \[ \text{CSA}_1 = 2 \pi r_1 h_1 \] \[ \text{CSA}_2 = 2 \pi r_2 h_2 \] 3. **Set Up the Ratio of Curved Surface Areas**: - The ratio of the curved surface areas of the two cylinders can be written as: \[ \frac{\text{CSA}_1}{\text{CSA}_2} = \frac{2 \pi r_1 h_1}{2 \pi r_2 h_2} \] - The \( 2 \pi \) terms will cancel out: \[ \frac{\text{CSA}_1}{\text{CSA}_2} = \frac{r_1 h_1}{r_2 h_2} \] 4. **Substituting the Ratios**: - Substitute the ratios of the radii and heights into the equation: \[ \frac{r_1}{r_2} = \frac{3}{5} \quad \text{and} \quad \frac{h_1}{h_2} = \frac{2}{3} \] - Therefore, we can express the ratio of the curved surface areas as: \[ \frac{\text{CSA}_1}{\text{CSA}_2} = \frac{3}{5} \times \frac{2}{3} \] 5. **Calculating the Final Ratio**: - Now, multiply the two fractions: \[ \frac{\text{CSA}_1}{\text{CSA}_2} = \frac{3 \times 2}{5 \times 3} = \frac{6}{15} \] - Simplifying \( \frac{6}{15} \) gives: \[ \frac{6}{15} = \frac{2}{5} \] 6. **Final Answer**: - The ratio of the curved surface areas of the two cylinders is: \[ \text{CSA}_1 : \text{CSA}_2 = 2 : 5 \]
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ICSE-CYLINDER, CONE AND SPHERE -EXERCISE 20 (A)
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