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The vertices of a DeltaABC are A(3, 8), ...

The vertices of a `DeltaABC` are A(3, 8), B(-1, 2) and C(6, 6). Find :
(i) Slope of BC.
(ii) Equation of a line perpendicular to BC and passing through A.

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The correct Answer is:
`(i) -(8)/(7) (ii) 7x-8y+43=0`
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