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If the mid-point of the line segment joining the points A(3, 4), B(k, 6) is P(x, y) and x + y - 10 = 0, find the value of k.

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To find the value of \( k \) given the points \( A(3, 4) \) and \( B(k, 6) \), and the condition that the midpoint \( P(x, y) \) lies on the line \( x + y - 10 = 0 \), we can follow these steps: ### Step 1: Find the Midpoint Coordinates The formula for the midpoint \( P \) of a line segment joining two points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) is given by: \[ P\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \] For points \( A(3, 4) \) and \( B(k, 6) \): - \( x_1 = 3 \), \( y_1 = 4 \) - \( x_2 = k \), \( y_2 = 6 \) Thus, the coordinates of the midpoint \( P \) are: \[ P\left(\frac{3 + k}{2}, \frac{4 + 6}{2}\right) \] Calculating \( y \): \[ y = \frac{4 + 6}{2} = \frac{10}{2} = 5 \] So, the coordinates of \( P \) are: \[ P\left(\frac{3 + k}{2}, 5\right) \] ### Step 2: Use the Condition of the Line The midpoint \( P \) lies on the line defined by the equation: \[ x + y - 10 = 0 \] Substituting the coordinates of \( P \) into the equation: \[ \frac{3 + k}{2} + 5 - 10 = 0 \] ### Step 3: Simplify the Equation Now, simplify the equation: \[ \frac{3 + k}{2} + 5 - 10 = 0 \] This simplifies to: \[ \frac{3 + k}{2} - 5 = 0 \] \[ \frac{3 + k}{2} = 5 \] ### Step 4: Solve for \( k \) Now, multiply both sides by 2 to eliminate the fraction: \[ 3 + k = 10 \] Subtract 3 from both sides: \[ k = 10 - 3 \] \[ k = 7 \] ### Conclusion The value of \( k \) is \( 7 \). ---
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ICSE-REVISION PAPER -1 -SECTION B
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