Metallic spheres of diameters 12 cm, 16 cm and 20 cm respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere.
Metallic spheres of diameters 12 cm, 16 cm and 20 cm respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere.
Text Solution
AI Generated Solution
The correct Answer is:
To find the radius of the resulting sphere formed by melting three metallic spheres with diameters of 12 cm, 16 cm, and 20 cm, we can follow these steps:
### Step 1: Calculate the radius of each sphere
The radius of a sphere is half of its diameter.
- For the sphere with a diameter of 12 cm:
\[
r_1 = \frac{12}{2} = 6 \text{ cm}
\]
- For the sphere with a diameter of 16 cm:
\[
r_2 = \frac{16}{2} = 8 \text{ cm}
\]
- For the sphere with a diameter of 20 cm:
\[
r_3 = \frac{20}{2} = 10 \text{ cm}
\]
### Step 2: Calculate the volume of each sphere
The volume \( V \) of a sphere is given by the formula:
\[
V = \frac{4}{3} \pi r^3
\]
- Volume of the first sphere:
\[
V_1 = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288 \pi \text{ cm}^3
\]
- Volume of the second sphere:
\[
V_2 = \frac{4}{3} \pi (8)^3 = \frac{4}{3} \pi (512) = \frac{2048}{3} \pi \text{ cm}^3
\]
- Volume of the third sphere:
\[
V_3 = \frac{4}{3} \pi (10)^3 = \frac{4}{3} \pi (1000) = \frac{4000}{3} \pi \text{ cm}^3
\]
### Step 3: Calculate the total volume of the three spheres
Now, we add the volumes of the three spheres:
\[
V_{total} = V_1 + V_2 + V_3 = 288 \pi + \frac{2048}{3} \pi + \frac{4000}{3} \pi
\]
To add these volumes, we need a common denominator:
\[
V_{total} = 288 \pi + \left(\frac{2048 + 4000}{3}\right) \pi = 288 \pi + \frac{6048}{3} \pi
\]
Convert \( 288 \) to a fraction with a denominator of 3:
\[
288 = \frac{864}{3}
\]
Thus,
\[
V_{total} = \frac{864}{3} \pi + \frac{6048}{3} \pi = \frac{6912}{3} \pi \text{ cm}^3
\]
### Step 4: Set the total volume equal to the volume of the resulting sphere
Let the radius of the resulting sphere be \( r \). The volume of the resulting sphere is:
\[
V = \frac{4}{3} \pi r^3
\]
Setting the total volume equal to the volume of the resulting sphere:
\[
\frac{4}{3} \pi r^3 = \frac{6912}{3} \pi
\]
### Step 5: Cancel out \( \frac{4}{3} \pi \) from both sides
\[
r^3 = \frac{6912}{4} = 1728
\]
### Step 6: Calculate the radius
To find \( r \), take the cube root of 1728:
\[
r = \sqrt[3]{1728} = 12 \text{ cm}
\]
### Final Answer
The radius of the resulting sphere is **12 cm**.
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