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Metallic spheres of diameters 12 cm, 16 ...

Metallic spheres of diameters 12 cm, 16 cm and 20 cm respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere.

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To find the radius of the resulting sphere formed by melting three metallic spheres with diameters of 12 cm, 16 cm, and 20 cm, we can follow these steps: ### Step 1: Calculate the radius of each sphere The radius of a sphere is half of its diameter. - For the sphere with a diameter of 12 cm: \[ r_1 = \frac{12}{2} = 6 \text{ cm} \] - For the sphere with a diameter of 16 cm: \[ r_2 = \frac{16}{2} = 8 \text{ cm} \] - For the sphere with a diameter of 20 cm: \[ r_3 = \frac{20}{2} = 10 \text{ cm} \] ### Step 2: Calculate the volume of each sphere The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] - Volume of the first sphere: \[ V_1 = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288 \pi \text{ cm}^3 \] - Volume of the second sphere: \[ V_2 = \frac{4}{3} \pi (8)^3 = \frac{4}{3} \pi (512) = \frac{2048}{3} \pi \text{ cm}^3 \] - Volume of the third sphere: \[ V_3 = \frac{4}{3} \pi (10)^3 = \frac{4}{3} \pi (1000) = \frac{4000}{3} \pi \text{ cm}^3 \] ### Step 3: Calculate the total volume of the three spheres Now, we add the volumes of the three spheres: \[ V_{total} = V_1 + V_2 + V_3 = 288 \pi + \frac{2048}{3} \pi + \frac{4000}{3} \pi \] To add these volumes, we need a common denominator: \[ V_{total} = 288 \pi + \left(\frac{2048 + 4000}{3}\right) \pi = 288 \pi + \frac{6048}{3} \pi \] Convert \( 288 \) to a fraction with a denominator of 3: \[ 288 = \frac{864}{3} \] Thus, \[ V_{total} = \frac{864}{3} \pi + \frac{6048}{3} \pi = \frac{6912}{3} \pi \text{ cm}^3 \] ### Step 4: Set the total volume equal to the volume of the resulting sphere Let the radius of the resulting sphere be \( r \). The volume of the resulting sphere is: \[ V = \frac{4}{3} \pi r^3 \] Setting the total volume equal to the volume of the resulting sphere: \[ \frac{4}{3} \pi r^3 = \frac{6912}{3} \pi \] ### Step 5: Cancel out \( \frac{4}{3} \pi \) from both sides \[ r^3 = \frac{6912}{4} = 1728 \] ### Step 6: Calculate the radius To find \( r \), take the cube root of 1728: \[ r = \sqrt[3]{1728} = 12 \text{ cm} \] ### Final Answer The radius of the resulting sphere is **12 cm**. ---
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