ABC is a right-angled triangle with the right angle at vertex B. BD is the altitude through B. Given BD = 12 cm and AD = 9 cm. Find AC.
Text Solution
AI Generated Solution
The correct Answer is:
To find the length of AC in the right-angled triangle ABC, we can use the properties of right triangles and the altitude drawn from the right angle.
### Step-by-Step Solution:
1. **Identify the given values**:
- BD (altitude from B to AC) = 12 cm
- AD = 9 cm
2. **Use the property of right triangles**:
In a right triangle, the square of the length of the altitude (BD) from the right angle to the hypotenuse (AC) is equal to the product of the segments into which it divides the hypotenuse (AD and DC). This can be expressed as:
\[
BD^2 = AD \cdot DC
\]
3. **Substitute the known values into the equation**:
\[
12^2 = 9 \cdot DC
\]
\[
144 = 9 \cdot DC
\]
4. **Solve for DC**:
\[
DC = \frac{144}{9} = 16 \text{ cm}
\]
5. **Find AC**:
The length of AC can be found by adding the lengths of AD and DC:
\[
AC = AD + DC
\]
\[
AC = 9 + 16 = 25 \text{ cm}
\]
### Final Answer:
The length of AC is **25 cm**.
Topper's Solved these Questions
REVISION PAPER -2
ICSE|Exercise SECTION B|1 Videos
REVISION PAPER -1
ICSE|Exercise SECTION B|25 Videos
REVISION PAPER -3
ICSE|Exercise SECTION - B|22 Videos
Similar Questions
Explore conceptually related problems
ABC is a right-angled triangle with the right angle at vertex B. BD is the altitude through B. Given BD = 12 cm and AD = 9 cm. Calculate AB .
ABC is a right-angled triangle with the right angle at vertex B. BD is the altitude through B.given BD=12cm and AD=9cm. Name the triangles which are similar to triangle ADB (Proof not required).
In the given, figure triangle ABC is right angled at B. D is the foot of the perpendicular from B to AC. Given that BC = 3 cm and AB = 4 cm. Find : (i) tan angle DBC (ii) sin angle DBA
In the adjoining figure, ABC is a triangle right-angled at vertex A and AD is altitude. If BD = 3.6 cm and CD = 6.4 cm, find the length of AD.
ABC is a isosceles right angled triangle, right angled at C. prove that AB^(2) = 2AC^(2)
ABC is a right angled triangle of which A is the right angle, BD is drawn perpendicular to BC meets CA produced in D. If AB = 12, AC = 16, BC = 20, then BD =
If triangle ABC is right angled at C, then the value of sec (A+B) is
A B C is a right angled triangle, right angled at B such that B C=6c m and A B=8c m . A circle with centre O is inscribed in A B C . The radius of the circle is (a) 1cm (b) 2cm (c) 3cm (d) 4cm
In the given figure AD is the bisector of angleA . If BD= 4 cm , DC = 3 cm and AB = 6cm . Find AC.
In a right angled triangle, find the length of the hypotenuse, if the other two sides measure 12 cm and 35 cm.