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Four cards are drawn from a full pack of...

Four cards are drawn from a full pack of cards . Find the probability that
all are diamonds ,

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The correct Answer is:
To find the probability that all four cards drawn from a full pack of cards are diamonds, we can follow these steps: ### Step 1: Understand the Total Outcomes A standard deck of cards contains 52 cards. We need to determine the total number of ways to draw 4 cards from these 52 cards. This can be calculated using the combination formula: \[ \text{Total Outcomes} = \binom{52}{4} \] ### Step 2: Calculate the Total Outcomes Using the combination formula, we can express this as: \[ \binom{52}{4} = \frac{52!}{4!(52-4)!} = \frac{52!}{4! \cdot 48!} \] ### Step 3: Understand the Favorable Outcomes Next, we need to find the number of favorable outcomes, which is the number of ways to draw 4 diamonds from the 13 diamonds available in the deck. This can also be calculated using the combination formula: \[ \text{Favorable Outcomes} = \binom{13}{4} \] ### Step 4: Calculate the Favorable Outcomes Using the combination formula again, we can express this as: \[ \binom{13}{4} = \frac{13!}{4!(13-4)!} = \frac{13!}{4! \cdot 9!} \] ### Step 5: Set Up the Probability Formula The probability of drawing 4 diamonds can be calculated using the formula for probability: \[ P(\text{All Diamonds}) = \frac{\text{Favorable Outcomes}}{\text{Total Outcomes}} = \frac{\binom{13}{4}}{\binom{52}{4}} \] ### Step 6: Substitute and Simplify Substituting the values we calculated: \[ P(\text{All Diamonds}) = \frac{\frac{13!}{4! \cdot 9!}}{\frac{52!}{4! \cdot 48!}} \] The \(4!\) cancels out: \[ P(\text{All Diamonds}) = \frac{13! \cdot 48!}{9! \cdot 52!} \] ### Step 7: Cancel the Factorials Now we can cancel \(9!\) and \(48!\): \[ P(\text{All Diamonds}) = \frac{13 \times 12 \times 11 \times 10}{52 \times 51 \times 50 \times 49} \] ### Step 8: Calculate the Final Probability Now we compute the values: \[ P(\text{All Diamonds}) = \frac{17160}{6497400} \] ### Step 9: Simplify the Fraction On simplifying: \[ P(\text{All Diamonds}) = \frac{11}{4165} \] Thus, the probability that all four cards drawn are diamonds is: \[ \boxed{\frac{11}{4165}} \]
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