Nine counters numbered 2 to 10 are put in a bag . One counter is selected at random . What is the probility of getting a counter with :
not an odd number

Answer

To solve the problem of finding the probability of selecting a counter that is not an odd number from a bag containing counters numbered from 2 to 10, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Total Number of Counters:**
The counters are numbered from 2 to 10. Therefore, the total number of counters is:
\[ 10 - 2 + 1 = 9 \]
So, there are 9 counters in total.

2. **List the Counters:**
The counters are: 2, 3, 4, 5, 6, 7, 8, 9, 10.

3. **Identify the Odd and Even Numbers:**
- Odd numbers from the list: 3, 5, 7, 9 (Total = 4 odd numbers)
- Even numbers from the list: 2, 4, 6, 8, 10 (Total = 5 even numbers)

4. **Determine the Favorable Outcomes:**
We are interested in counters that are **not odd numbers**, which means we are looking for even numbers. The even numbers are: 2, 4, 6, 8, and 10. Thus, the number of favorable outcomes (even numbers) is:
\[ 5 \]

5. **Calculate the Probability:**
The probability \( P \) of selecting a counter that is not an odd number is given by the formula:
\[ P(\text{not odd}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{5}{9} \]

### Final Answer:
The probability of getting a counter that is not an odd number is:
\[ \frac{5}{9} \]