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A bag contains 20 balls . These are of ...

A bag contains 20 balls . These are of three different colours : green red and blue .A ball is chosen at random from the bag . The probability of a green ball is `(1)/(4)`. The probability of a red ball is `(2)/(5)` .
What is the probability of a blue ball ?

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To find the probability of drawing a blue ball from the bag, we can follow these steps: ### Step 1: Understand the total probability The total probability of all possible outcomes (drawing a green ball, a red ball, or a blue ball) must equal 1. Therefore, we can express this as: \[ P(\text{Green}) + P(\text{Red}) + P(\text{Blue}) = 1 \] ### Step 2: Substitute known probabilities We know the probabilities of drawing a green ball and a red ball: - \( P(\text{Green}) = \frac{1}{4} \) - \( P(\text{Red}) = \frac{2}{5} \) Substituting these values into the equation gives: \[ \frac{1}{4} + \frac{2}{5} + P(\text{Blue}) = 1 \] ### Step 3: Find a common denominator To combine the fractions, we need a common denominator. The denominators are 4 and 5, and the least common multiple (LCM) of 4 and 5 is 20. We will convert each fraction: - Convert \( \frac{1}{4} \) to have a denominator of 20: \[ \frac{1}{4} = \frac{5}{20} \] - Convert \( \frac{2}{5} \) to have a denominator of 20: \[ \frac{2}{5} = \frac{8}{20} \] ### Step 4: Substitute back into the equation Now we substitute these converted fractions back into the equation: \[ \frac{5}{20} + \frac{8}{20} + P(\text{Blue}) = 1 \] ### Step 5: Combine the fractions Combine the fractions on the left side: \[ \frac{5 + 8}{20} + P(\text{Blue}) = 1 \] This simplifies to: \[ \frac{13}{20} + P(\text{Blue}) = 1 \] ### Step 6: Solve for \( P(\text{Blue}) \) To find \( P(\text{Blue}) \), we subtract \( \frac{13}{20} \) from 1: \[ P(\text{Blue}) = 1 - \frac{13}{20} \] Convert 1 to a fraction with a denominator of 20: \[ P(\text{Blue}) = \frac{20}{20} - \frac{13}{20} = \frac{7}{20} \] ### Final Answer Thus, the probability of drawing a blue ball is: \[ \boxed{\frac{7}{20}} \]
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ICSE-PROBABILITY -EXERCISE 22 (B)
  1. A bag contains 20 coloured balls . 8 are red , 6 are blue ,3 are green...

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  2. A bag contains 20 coloured balls . 8 are red , 6 are blue ,3 are gree...

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  3. A bag contains 20 coloured balls . 8 are red , 6 are blue ,3 are gree...

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  4. A bag contains 20 balls . These are of three different colours : gree...

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  5. A bag contains 20 balls . These are of three different colours : gree...

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  6. A bag contains 20 balls . These are of three different colours : gree...

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  7. A bag contains 20 balls . These are of three different colours : gree...

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  8. A pair of dice is thrown . Find the probability of getting a sum of 1...

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  9. A match can be won , drawn or lost One week a school it to play two ma...

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  10. A match can be won , drawn or lost One week a school it to play two ma...

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  11. A match can be won , drawn or lost One week a school it to play two ma...

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  12. A match can be won , drawn or lost One week a school it to play two ma...

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  13. A match can be won , drawn or lost One week a school it to play two ma...

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  14. The ace , king, queen , jack and ten from both the spades and hearts s...

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  15. The ace , king queen , jack and ten from both the spades and hearts su...

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  16. The ace , king queen , jack and ten from both the spades and hearts su...

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  17. The ace , king queen , jack and ten from both the spades and hearts su...

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  18. The ace , king queen , jack and ten from both the spades and hearts su...

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  19. A small pack of cards consists of the Ace, King, Queen, Jack and ten o...

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  20. The ace , king queen , jack and ten from both the spades and hearts su...

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