In a single throw of two dice , what is the probability of
doublets ?

Answer

To find the probability of getting doublets when throwing two dice, we can follow these steps:

### Step 1: Determine the total number of outcomes
When throwing two dice, each die has 6 faces. Therefore, the total number of outcomes when throwing two dice is calculated as follows:

\[ \text{Total Outcomes} = 6 \times 6 = 36 \]

### Step 2: Identify the favorable outcomes (doublets)
Doublets occur when both dice show the same number. The possible doublets are:

- (1, 1)
- (2, 2)
- (3, 3)
- (4, 4)
- (5, 5)
- (6, 6)

Counting these, we find there are 6 favorable outcomes.

### Step 3: Calculate the probability of getting doublets
The probability \( P \) of an event is given by the formula:

\[ P(\text{Event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} \]

Substituting the values we found:

\[ P(\text{Doublets}) = \frac{6}{36} = \frac{1}{6} \]

### Final Answer
The probability of getting doublets when throwing two dice is \( \frac{1}{6} \).

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