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Four cards are drawn at random from a p...

Four cards are drawn at random from a pack of 52 playing cards , Find the probability of getting
all cards of the same colour ,

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To solve the problem of finding the probability of drawing four cards of the same color from a standard deck of 52 playing cards, we can follow these steps: ### Step 1: Determine the total number of ways to select 4 cards from 52 cards. The total number of ways to select 4 cards from a deck of 52 cards is given by the combination formula: \[ \text{Total ways} = \binom{52}{4} \] ### Step 2: Determine the number of red and black cards in the deck. In a standard deck of cards, there are: - 26 red cards (13 hearts and 13 diamonds) - 26 black cards (13 clubs and 13 spades) ### Step 3: Calculate the number of ways to select 4 red cards. The number of ways to select 4 cards from the 26 red cards is: \[ \text{Ways to select 4 red cards} = \binom{26}{4} \] ### Step 4: Calculate the number of ways to select 4 black cards. Similarly, the number of ways to select 4 cards from the 26 black cards is: \[ \text{Ways to select 4 black cards} = \binom{26}{4} \] ### Step 5: Calculate the total number of favorable outcomes. The total number of favorable outcomes for getting 4 cards of the same color (either all red or all black) is: \[ \text{Favorable outcomes} = \binom{26}{4} + \binom{26}{4} = 2 \cdot \binom{26}{4} \] ### Step 6: Calculate the probability. The probability of drawing 4 cards of the same color is given by the ratio of the number of favorable outcomes to the total number of outcomes: \[ P(\text{same color}) = \frac{\text{Favorable outcomes}}{\text{Total ways}} = \frac{2 \cdot \binom{26}{4}}{\binom{52}{4}} \] ### Step 7: Substitute the values and simplify. Now we can calculate the combinations: \[ \binom{26}{4} = \frac{26 \times 25 \times 24 \times 23}{4 \times 3 \times 2 \times 1} = 14950 \] \[ \binom{52}{4} = \frac{52 \times 51 \times 50 \times 49}{4 \times 3 \times 2 \times 1} = 270725 \] Now substituting these values into the probability formula: \[ P(\text{same color}) = \frac{2 \cdot 14950}{270725} = \frac{29900}{270725} \] ### Step 8: Simplify the fraction. After simplifying, we find: \[ P(\text{same color}) \approx \frac{92}{833} \] Thus, the final answer is: \[ \text{Probability of getting all cards of the same color} = \frac{92}{833} \] ---
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ICSE-PROBABILITY -EXERCISE 22 (D )
  1. Four cards are drawn at random from a pack of 52 playing cards , Find...

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  2. Four cards are drawn at random from a pack of 52 playing cards , Find...

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  3. Four cards are drawn at random from a pack of 52 playing cards , Find...

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  4. Four cards are drawn at random from a pack of 52 playing cards , Find...

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  5. Four cards are drawn at random from a pack of 52 playing cards. Find ...

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  6. In a Iottery of 50 tickets numbered 1 to 50 , two tickets are drawn si...

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  7. In a Iottery of 50 tickets numbered 1 to 50 , two tickets are drawn si...

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  8. In a Iottery of 50 tickets numbered 1 to 50 , two tickets are drawn si...

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  9. Out of 9 outstanding students in a college, there are 4 boys and 5 ...

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  10. Four people are chosen at random from a group consisting of 3 men , 2...

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  11. A commitree of 5 principals is to be selected from a group of 6 gent p...

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  12. A bag contains tickets numbered 1 to 20 . Two tickets are drawn . Fin...

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  13. A bag contains tickets numbered 1 to 30. Three tickets are drawn at ...

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  14. A room has 3 lamps . From a collection of 10 light bulbs of which 6 ar...

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  15. A has 3 shares in a lottery containing 3 prizes and 9 blanks , B has ...

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  16. There are n letters and n addressed envelopes . If the letters are pla...

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  17. Three letters are written to different persons , and the addresses on ...

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  18. The letters of SOCIETY are placed at random in a row. What is the p...

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  19. In a random arrangement of the letters of the "COMMERCE" , find the p...

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  20. Given a group of 4 persoms , find the probability that no two of th...

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