Sameer throws , an ordinary die . What is the probability that he throws
2 or 5 ?

Answer

To solve the problem of finding the probability that Sameer throws a 2 or a 5 when throwing an ordinary die, we can follow these steps:

### Step 1: Identify the total number of outcomes
When throwing an ordinary die, the possible outcomes are the numbers on the die faces, which are 1, 2, 3, 4, 5, and 6. Therefore, the total number of outcomes is:
- Total outcomes = 6

### Step 2: Identify the favorable outcomes
We need to find the outcomes that are favorable to our event, which is throwing a 2 or a 5. The favorable outcomes in this case are:
- Favorable outcomes = {2, 5}

Thus, the number of favorable outcomes is:
- Number of favorable outcomes = 2 (since there are two outcomes: 2 and 5)

### Step 3: Calculate the probability
The probability of an event is given by the formula:
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Substituting the values we found:
\[ \text{Probability} = \frac{2}{6} \]

### Step 4: Simplify the probability
Now, we simplify the fraction:
\[ \frac{2}{6} = \frac{1}{3} \]

### Final Answer
Thus, the probability that Sameer throws a 2 or a 5 is:
\[ \frac{1}{3} \]

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