A bag contains 7 white balls ,9 green balls and 10 yellow balls . A ball is drawn at random from the bag . What is the probability that it will be
neither yellow nor green ?

Answer

To solve the problem step by step, we will calculate the probability of drawing a ball that is neither yellow nor green from the bag.

### Step 1: Determine the total number of balls in the bag.
- The bag contains:
- 7 white balls
- 9 green balls
- 10 yellow balls

**Total number of balls = Number of white balls + Number of green balls + Number of yellow balls**
\[ \text{Total} = 7 + 9 + 10 = 26 \]

### Step 2: Identify the number of favorable outcomes.
- We want to find the probability of drawing a ball that is neither yellow nor green. This means we are only interested in the white balls.
- The number of white balls is 7.

### Step 3: Calculate the probability.
- Probability is defined as the number of favorable outcomes divided by the total number of outcomes.
\[ \text{Probability of drawing a white ball} = \frac{\text{Number of white balls}}{\text{Total number of balls}} = \frac{7}{26} \]

### Conclusion:
The probability that a ball drawn at random from the bag will be neither yellow nor green is \(\frac{7}{26}\).

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