Find the perimeter and area of a rectangle having :
Length = 16 cm , Breadth = 12 cm

Answer

To find the perimeter and area of a rectangle with a length of 16 cm and a breadth of 12 cm, we can follow these steps:

### Step 1: Calculate the Perimeter
The formula for the perimeter (P) of a rectangle is given by:
\[ P = 2 \times (l + b) \]
where \( l \) is the length and \( b \) is the breadth.

Substituting the given values:
\[ P = 2 \times (16 \, \text{cm} + 12 \, \text{cm}) \]

### Step 2: Simplify Inside the Parentheses
Now, we calculate the sum inside the parentheses:
\[ 16 \, \text{cm} + 12 \, \text{cm} = 28 \, \text{cm} \]

### Step 3: Multiply by 2
Now, we multiply the result by 2:
\[ P = 2 \times 28 \, \text{cm} = 56 \, \text{cm} \]

### Step 4: Calculate the Area
The formula for the area (A) of a rectangle is given by:
\[ A = l \times b \]

Substituting the given values:
\[ A = 16 \, \text{cm} \times 12 \, \text{cm} \]

### Step 5: Perform the Multiplication
Now, we calculate the area:
\[ A = 192 \, \text{cm}^2 \]

### Final Answer
Thus, the perimeter of the rectangle is \( 56 \, \text{cm} \) and the area is \( 192 \, \text{cm}^2 \).

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