Find the perimeter and area of a rectangle having :
Length = 8 m , Breadth =9 dm

Answer

To find the perimeter and area of a rectangle with the given dimensions, we will follow these steps:

### Step 1: Convert the measurements to the same unit
The length is given in meters and the breadth in decimeters. We need to convert the length from meters to decimeters.

- **Length = 8 meters**
- **Breadth = 9 decimeters**

Since 1 meter = 10 decimeters, we convert the length:
\[ \text{Length in decimeters} = 8 \, \text{m} \times 10 = 80 \, \text{dm} \]

### Step 2: Calculate the perimeter of the rectangle
The formula for the perimeter \( P \) of a rectangle is:
\[ P = 2 \times (\text{Length} + \text{Breadth}) \]
Substituting the values:
\[ P = 2 \times (80 \, \text{dm} + 9 \, \text{dm}) \]
\[ P = 2 \times 89 \, \text{dm} \]
\[ P = 178 \, \text{dm} \]

### Step 3: Calculate the area of the rectangle
The formula for the area \( A \) of a rectangle is:
\[ A = \text{Length} \times \text{Breadth} \]
Substituting the values:
\[ A = 80 \, \text{dm} \times 9 \, \text{dm} \]
\[ A = 720 \, \text{dm}^2 \]

### Final Answers:
- **Perimeter = 178 dm**
- **Area = 720 dm²**

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