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Find the area of the triangle whose sides are 50 cm , 48 cm and 14 cm .Find the heigth of triangle corresponding to the side measuring 48 cm .

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To solve the problem of finding the area of a triangle with sides measuring 50 cm, 48 cm, and 14 cm, and then finding the height corresponding to the side measuring 48 cm, we can follow these steps: ### Step 1: Calculate the semi-perimeter (s) of the triangle. The semi-perimeter \( s \) is calculated using the formula: \[ s = \frac{a + b + c}{2} \] where \( a = 50 \, \text{cm} \), \( b = 48 \, \text{cm} \), and \( c = 14 \, \text{cm} \). Calculating: \[ s = \frac{50 + 48 + 14}{2} = \frac{112}{2} = 56 \, \text{cm} \] ### Step 2: Use Heron's formula to find the area of the triangle. Heron's formula states that the area \( A \) of the triangle can be calculated as: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \] Substituting the values: \[ A = \sqrt{56(56-50)(56-48)(56-14)} \] Calculating each term: \[ A = \sqrt{56 \times 6 \times 8 \times 42} \] ### Step 3: Simplify the expression under the square root. Calculating: \[ A = \sqrt{56 \times 6 \times 8 \times 42} \] We can break this down: \[ 56 = 7 \times 8, \quad 6 = 3 \times 2, \quad 42 = 6 \times 7 \] So, \[ A = \sqrt{(7 \times 8) \times (3 \times 2) \times (8) \times (6 \times 7)} \] Grouping the pairs: \[ A = \sqrt{(7^2) \times (8^2) \times (3 \times 2) \times 6} \] Taking the square root: \[ A = 7 \times 8 \times \sqrt{(3 \times 2) \times 6} = 7 \times 8 \times 6 = 336 \, \text{cm}^2 \] ### Step 4: Find the height corresponding to the base of 48 cm. To find the height \( h \) corresponding to the base \( b = 48 \, \text{cm} \), we use the area formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] Substituting the known values: \[ 336 = \frac{1}{2} \times 48 \times h \] ### Step 5: Solve for height \( h \). Multiplying both sides by 2: \[ 672 = 48 \times h \] Now, divide by 48: \[ h = \frac{672}{48} = 14 \, \text{cm} \] ### Final Answers: - The area of the triangle is \( 336 \, \text{cm}^2 \). - The height corresponding to the side measuring \( 48 \, \text{cm} \) is \( 14 \, \text{cm} \).
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ICSE-MENSURATION-EXERCISE 23 E
  1. Find the height of the triangle whose : area =56dm^(2) , base = 2....

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  4. Find the area of the triangle whose sides are 13 cm , 20 cm and 21 cm...

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  5. Find the area of the triangle whose sides are 50 cm , 48 cm and 14 cm ...

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  6. Find the area of an isosceles triangle in which each of the equal sid...

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  7. The base and the heigth of a triangle are in the ratio 5 : 3 and its...

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  8. Find the area and the height of an equilateral triangle whose each sid...

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  9. Find the area and the height of an equilateral triangle whose each sid...

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  10. Find the area and the height of an equilateral triangle whose each sid...

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  11. Find the area of a right triangle whose hypotenuse is 26 cm long and o...

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  12. The area of a right triangle is 240 cm^(2) and one of its legs is 16 ...

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  13. The legs of a right triangle are in the ratio 3 : 4 and its area is 10...

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  14. The sides of a triangle are in the ratio 13 : 14 : 15 and its per...

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  15. The base of an isosceles triangle is 12 cm and its perimeter is 32 ...

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  16. The cost of painting the top surface of a triangular board at 80 paise...

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  17. Calculate the area of the quadrilateral ABCD in which AB =BD =AD = ...

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  18. Calculate the area of the quadrilateral PQRS shown in the adjoining fi...

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  19. Find the area of a quadrilateral ABCD whose diagonal AC is 25 cm lon...

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  20. Find the area of the quadrilateral ABCD , given in the adjoining figur...

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