`sin^(2) x + cos ^(2) y = 1`

The values of x satisfying the system of equation 2^("sin" x + "cos"y) = 1, 16^("sin"^(2)x + "cos"^(2)y) =4 are given by

The number of ordered pair (x, y) satisfying the equation sin^(2) (x+y)+cos^(2) (x-y)=1 which lie on the circle x^(2)+y^(2)=pi^(2) is _________.

If sin^(-1) x + sin^(-1)y = pi//2 and cos^(-1) x - cos^(-1) y = 0 , then value x and y respectively

prove that: cos ^ (2) x + cos ^ (2) y-2cos x * cos y * cos (x + y) = sin ^ (2) (x + y)

Consider the system of equations x cos^(3) y+3x cos y sin^(2) y=14 x sin^(3) y+3x cos^(2) y sin y=13 The value of sin^(2) y+2 cos^(2) y is

If (cos ^ (4) x) / (cos ^ (2) y) + (sin ^ (4) x) / (sin ^ (2) y) = 1 then prove that (cos ^ (4) y) / (cos ^ (2) x) + (sin ^ (4) y) / (sin ^ (2) x) = 1

If 2^(sin x+cos y)=1 and 16^(sin^(2)x+cos^(2)y)=4 , then find the value of sin x and cos y

If sin^(-1) x + sin^(-1) y = (pi)/(2) and sin 2x = cos 2y , then

If sin ^ (- 1) x + sin ^ (- 1) y = (2 pi) / (3), then cos ^ (- 1) x + cos ^ (- 1) y =

If sin^(-1) x + sin^(-1) y = (2pi)/3", then " cos^(-1) x + cos^(-1) y