Two particles `A` and `B` each of mass `m` are kept stationary by applying a horizontal force `F = mg` on particle `B` as show in figure .Then

Two partical A and B each of mass m are kept stationary by applying a horizontal force F = mg on partical B as show in figure .Then

Two particles A and B, each of mass m, are kept stationary by appyling a horizontal force F=mg on particle B as shown in fig.

Two particle A & B each of mass m are in equilibrium in a vertical plane under action of a horizontal force F=mg on particle B, as shown in figure Then :

Four particles A,B, C and D each of mass m are kept at the corners of a square of side L. Now the particle D is taken to infinity by an external agent keeping the other particles fixed at their respective positions . The work done by the gravitational force acting on the particle D During its movement is

Two identicle particles A and B, each of mass m, are interconnected by a spring of stiffness k. If particle B experiences a forec F and the elongation of the spring is x, the acceleration of particle B relative to particle A is equal to

Two small particles P and Q each of mass m are fixed along x-axis at points (a,0) and (-a,0). A third particle R is kept at origin. Then

Two blocks 'A' and 'B' each of mass 'm' are placed on a smooth horizontal surface . Two horizontal force F and 2F are applied on the blocks A and B , respectively , as shown in figure . The block A does not slide on block B . The normal reaction acting between the two blocks is

Two blocks A and B each of mass m are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on blocks A and B, respectively, as shown in fig. Block A does not slide on block B. Then then the normal reaction acting between the two blocks is (assume no friction between the blocks)

Three particles A, B and C of mass m, m and 2m lie in a straight line as shown. The only force acting on these particles is due to the gravitational attraction towards each other. Let the magnitude of net force on them be F_(A), F_(B) and F_(C ) respectively. Then, F_(A):F_(B):F_(C ) is equal to :

Three particles, each of mass m are fixed at the vertices of an equilateral triangle of side length a . The only forces acting on the particles are their mutual gravitational forces. Then answer the following questions. Force acting on particle C , due to particle A and B