If `(tan(alpha+beta+gamma))/("tan"(alpha-beta-gamma))=(tangamma)/(tanbeta),(beta!=gamma)` then `sin2alpha+s in2beta+s in2gamma=` 0 (b) 1 (c) 2 (d)

If (tan(alpha+beta-gamma))/(tan(alpha-beta+gamma))=(tan gamma)/(tan beta),(beta!=gamma) then sin2 alpha+sin2 beta+sin2 gamma=(a)0(b)1(c)2(d)(1)/(2)

If (tan(alpha +beta - gamma))/(tan(alpha -beta + gamma)) = (tan gamma/tan beta) show that sin(beta -gamma) =0 or sin(beta -gamma) =0 , or sin2 alpha +sin2 beta + sin2 gamma =0

If tan beta=(tan alpha+tan gamma)/(1+tan alpha tan gamma)* prove that sin2 beta=(sin2 alpha+sin2 gamma)/(1+sin2 alpha sin2 gamma)

Prove that: tan(alpha-beta)+tan(beta-gamma)+tan (gamma-alpha) = tan(alpha-beta) tan (beta-gamma) tan (gamma-alpha) .

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and gamma are in

If cos(alpha + gamma)/cos(alpha - gamma) = cos 2beta then tan alpha, tan beta and tan gamma are

If alpha,beta,gamma,in(0,(pi)/(2)), then prove that (si(alpha+beta+gamma))/(sin alpha+sin beta+sin gamma)<1

If 0

If tan beta=(tan alpha + tan gamma)/(1+ tan alpha . tan gamma) Prove that sin 2 beta =(sin 2 alpha + sin 2 gamma)/(1+ sin 2 alpha . Sin 2 gamma)

sin (beta+ gamma- alpha) + sin (gamma+ alpha - beta) + sin (alpha + beta- gamma)- sin (alpha + beta + gamma)=