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The number of subsets of a set containi...

The number of subsets of a set containing n elements is :

A

n

B

`2^(n)-1`

C

`2^(n-1)`

D

`2^(n)`

Text Solution

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The correct Answer is:
To find the number of subsets of a set containing \( n \) elements, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We need to determine how many subsets can be formed from a set that has \( n \) elements. 2. **Choosing Elements**: For a set with \( n \) elements, we can choose: - 0 elements (which gives us the empty set), - 1 element, - 2 elements, - and so on, up to \( n \) elements (which gives us the set itself). 3. **Using Combinations**: The number of ways to choose \( k \) elements from \( n \) elements is given by the binomial coefficient \( \binom{n}{k} \). Therefore, the number of subsets can be expressed as: \[ \text{Number of subsets} = \binom{n}{0} + \binom{n}{1} + \binom{n}{2} + \ldots + \binom{n}{n} \] 4. **Applying the Binomial Theorem**: According to the binomial theorem, we know that: \[ (1 + x)^n = \sum_{k=0}^{n} \binom{n}{k} x^k \] If we set \( x = 1 \), we get: \[ (1 + 1)^n = \sum_{k=0}^{n} \binom{n}{k} \cdot 1^k = \sum_{k=0}^{n} \binom{n}{k} \] This simplifies to: \[ 2^n = \sum_{k=0}^{n} \binom{n}{k} \] 5. **Conclusion**: Therefore, the total number of subsets of a set containing \( n \) elements is: \[ \text{Number of subsets} = 2^n \] ### Final Answer: The number of subsets of a set containing \( n \) elements is \( 2^n \). ---
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