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In sub - part (i) to (x) choose the correct option and in sub - part (xi) to (xy), answer the questions as intructed .
The derivative of `1+x+x^(2)+x(3)+….+x^(50)` at x=1:

A

1275

B

1725

C

1257

D

1255

Text Solution

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The correct Answer is:
To find the derivative of the function \( f(x) = 1 + x + x^2 + x^3 + \ldots + x^{50} \) at \( x = 1 \), we can follow these steps: ### Step 1: Write the function The function can be expressed as: \[ f(x) = 1 + x + x^2 + x^3 + \ldots + x^{50} \] ### Step 2: Find the derivative To find the derivative \( f'(x) \), we differentiate each term of the function: - The derivative of \( 1 \) is \( 0 \). - The derivative of \( x \) is \( 1 \). - The derivative of \( x^2 \) is \( 2x \). - The derivative of \( x^3 \) is \( 3x^2 \). - Continuing this pattern, the derivative of \( x^n \) is \( nx^{n-1} \). Thus, the derivative \( f'(x) \) is: \[ f'(x) = 0 + 1 + 2x + 3x^2 + 4x^3 + \ldots + 50x^{49} \] ### Step 3: Evaluate the derivative at \( x = 1 \) Now, we substitute \( x = 1 \) into the derivative: \[ f'(1) = 1 + 2(1) + 3(1^2) + 4(1^3) + \ldots + 50(1^{49}) \] This simplifies to: \[ f'(1) = 1 + 2 + 3 + 4 + \ldots + 50 \] ### Step 4: Calculate the sum The sum of the first \( n \) natural numbers can be calculated using the formula: \[ \text{Sum} = \frac{n(n + 1)}{2} \] For \( n = 50 \): \[ \text{Sum} = \frac{50(50 + 1)}{2} = \frac{50 \times 51}{2} = 1275 \] ### Conclusion Thus, the derivative of \( 1 + x + x^2 + x^3 + \ldots + x^{50} \) at \( x = 1 \) is: \[ \boxed{1275} \]
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