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A survey shows that 63% of the Americans...

A survey shows that `63%` of the Americans like cheese whereas `76%` like apples , If `x%` of the Americans like both cheese and apples , then find value of x .

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To solve the problem, we will use the principle of inclusion-exclusion in set theory. Let's denote: - \( N(A) \): the percentage of Americans who like cheese = 63% - \( N(B) \): the percentage of Americans who like apples = 76% - \( N(A \cap B) \): the percentage of Americans who like both cheese and apples = \( x \% \) - \( N(A \cup B) \): the percentage of Americans who like either cheese or apples or both = 100% According to the principle of inclusion-exclusion, we have: \[ N(A \cup B) = N(A) + N(B) - N(A \cap B) \] Substituting the known values into the equation: \[ 100 = 63 + 76 - x \] Now, let's simplify this equation step by step: 1. Combine the percentages of those who like cheese and apples: \[ 63 + 76 = 139 \] 2. Substitute this back into the equation: \[ 100 = 139 - x \] 3. Rearranging the equation to isolate \( x \): \[ x = 139 - 100 \] 4. Calculate the value of \( x \): \[ x = 39 \] Thus, the percentage of Americans who like both cheese and apples is \( \boxed{39\%} \).
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