Home
Class 11
MATHS
If the lines 2x+3y+1=0 and 3x-y-4=0 li...

If the lines `2x+3y+1=0` and `3x-y-4=0` lie along diameters of a circle of circumference `10 pi`, then the equation of the circle is

Text Solution

Verified by Experts

The correct Answer is:
`x^(2)+y^(2)-2x+2y-23=0`
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER - 18

    ICSE|Exercise SECTION - B|10 Videos

  • MODEL TEST PAPER - 18

    ICSE|Exercise SECTION - C|9 Videos

  • MOCK TEST PAPER-2021

    ICSE|Exercise SECTION - C|10 Videos

  • MODEL TEST PAPER - 10

    ICSE|Exercise SECTION - C |5 Videos

Similar Questions

Explore conceptually related problems

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameter of a circle of circumference 10pi , then show that the equation of the circle is x^(2)-y^(2)-2x+2y-23=0

If the lines 2x + 3y + 1 = 0 and 3x - y-4 = 0 lie along two diameters of a circle of circumference 10 pi , then the equation of circle is (i) x^(2) + y^(2) + 2x + 2y + 23 = 0 (ii) x^(2) + y^(2) - 2x - 2y - 23 = 0 (iii) x^(2) + y^(2) - 2 x + 2y - 23 = 0 (iv) x^(2) + y^(2) + 2x - 2y + 23 = 0

If the lines x+y+3=0 and 2x-y-9=0 lie along diameters of a circle of circumference 8pi then the equation of the circle is :

If the lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.

If the lines 3x + y = 11 and x - y = 1 are the diameters of a circle of area 154 sq. units, then the equation of the circle is

If the lines 3x-4y-7 = 0 and 2x-3y-5=0 are two diameters of a circle of area 49pi square units, the equation of the circle is:

The lines 2x-3y=5 and 3x-4y=7 are diameters of a circle of are 154 sq. units. Taking pi=22/7 , show that the equation of the circle is x^(2)+y^(2)-2x+2y=47

Let the lines 4x-3y+10=0 and 4x-3y-30=0 make equal intercepts of 6 units with a circle (C ) whose centre lies on 2x+y=0 , then the equation of the circle C is

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation 2x -y -2 =0 . Then the equation of the circle is:

The line 4x+3y-4=0 divides the circumference of the circle centred at (5,3) in the ratio 1:2. Then the equation of the circle is