Home
Class 11
MATHS
Find the coordinates of the points which...

Find the coordinates of the points which trisect the line segment joining the points P(4,2,-6) and Q(10,-16,6).

Text Solution

AI Generated Solution

The correct Answer is:
To find the coordinates of the points that trisect the line segment joining the points \( P(4, 2, -6) \) and \( Q(10, -16, 6) \), we will use the section formula. The points that trisect the line segment divide it into three equal parts. Let's denote the points that trisect the segment as \( R \) and \( S \). ### Step 1: Identify the points and the ratios The points \( P \) and \( Q \) are given as: - \( P(4, 2, -6) \) - \( Q(10, -16, 6) \) Since we want to trisect the line segment, we will divide it into three equal parts. The point \( R \) divides the segment \( PQ \) in the ratio \( 1:2 \) and the point \( S \) divides the segment \( PQ \) in the ratio \( 2:1 \). ### Step 2: Use the section formula for point \( R \) The section formula for a point dividing a line segment in the ratio \( m:n \) is given by: \[ \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}, \frac{mz_2 + nz_1}{m+n} \right) \] For point \( R \) (ratio \( 1:2 \)): - \( m = 1 \), \( n = 2 \) - \( (x_1, y_1, z_1) = (4, 2, -6) \) - \( (x_2, y_2, z_2) = (10, -16, 6) \) Calculating the coordinates of \( R \): - \( x_R = \frac{1 \cdot 10 + 2 \cdot 4}{1 + 2} = \frac{10 + 8}{3} = \frac{18}{3} = 6 \) - \( y_R = \frac{1 \cdot (-16) + 2 \cdot 2}{1 + 2} = \frac{-16 + 4}{3} = \frac{-12}{3} = -4 \) - \( z_R = \frac{1 \cdot 6 + 2 \cdot (-6)}{1 + 2} = \frac{6 - 12}{3} = \frac{-6}{3} = -2 \) Thus, the coordinates of point \( R \) are \( (6, -4, -2) \). ### Step 3: Use the section formula for point \( S \) For point \( S \) (ratio \( 2:1 \)): - \( m = 2 \), \( n = 1 \) Calculating the coordinates of \( S \): - \( x_S = \frac{2 \cdot 10 + 1 \cdot 4}{2 + 1} = \frac{20 + 4}{3} = \frac{24}{3} = 8 \) - \( y_S = \frac{2 \cdot (-16) + 1 \cdot 2}{2 + 1} = \frac{-32 + 2}{3} = \frac{-30}{3} = -10 \) - \( z_S = \frac{2 \cdot 6 + 1 \cdot (-6)}{2 + 1} = \frac{12 - 6}{3} = \frac{6}{3} = 2 \) Thus, the coordinates of point \( S \) are \( (8, -10, 2) \). ### Final Answer The coordinates of the points that trisect the line segment joining \( P \) and \( Q \) are: - Point \( R(6, -4, -2) \) - Point \( S(8, -10, 2) \)
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER - 18

    ICSE|Exercise SECTION - C|9 Videos
  • MODEL TEST PAPER - 18

    ICSE|Exercise SECTION - C|9 Videos
  • MOCK TEST PAPER-2021

    ICSE|Exercise SECTION - C|10 Videos
  • MODEL TEST PAPER - 10

    ICSE|Exercise SECTION - C |5 Videos

Similar Questions

Explore conceptually related problems

Find the coordinates of the points which trisect the line segment joining the points P(4,-2,-6)\ a n d\ Q(10 ,-16 ,6)dot

Find the coordinates of the points which trisect the line segment joining the points (2, 3) and (6, 5) .

Find the co-ordinates of the points of trisection of the line segment joining the points (2, 5) and (6, -2).

Find the coordinates of the points which divide the line segment joining the points (-4,\ 0) and (0,\ 6) in four equal parts.

Find the coordinates of the point which divides the line segment joining the point, (-2,3,5) and (1,-4,6) in the ratio. 2 : 3 internally,

Find the coordinates of the point which divides the line segment joining the point, (-2,3,5) and (1,-4,6) in the ratio. 2 : 3 externally,

Find the coordinates of the point which divides the line segment joining the points ( 2, 3, 5) and (1, 4, 6) in the ratio (i) 2 : 3 internally, (ii) 2 : 3 externally.

Find the co-ordinates of the points of trisection of the line segment joining the points A(-5, 6) and B (4, -3) .

Find the co-ordinates of the points of trisection of the line segment joining the points A(2, -3, 5) and B(6, 0, -1).

Find the coordinates of the points which trisect the line segment joining (2, 1, 0) and (5, 8, -3).