The total revenue in rupees received from the sale of x units of a product is given by `R(x)=300x- (x^(2))/(5)` Number of units when MR=0 is

Answer

To find the number of units when the marginal revenue (MR) is equal to zero, we will follow these steps:

### Step 1: Write down the total revenue function
The total revenue function is given by:
\[ R(x) = 300x - \frac{x^2}{5} \]

### Step 2: Find the marginal revenue function
Marginal revenue (MR) is the derivative of the total revenue function with respect to \( x \):
\[ MR = \frac{dR}{dx} \]

Calculating the derivative:
\[ MR = \frac{d}{dx}(300x) - \frac{d}{dx}\left(\frac{x^2}{5}\right) \]
\[ MR = 300 - \frac{2x}{5} \]

### Step 3: Set the marginal revenue equal to zero
To find the number of units when MR = 0, we set the marginal revenue function to zero:
\[ 300 - \frac{2x}{5} = 0 \]

### Step 4: Solve for \( x \)
Rearranging the equation:
\[ \frac{2x}{5} = 300 \]
Multiplying both sides by 5:
\[ 2x = 1500 \]
Now, divide by 2:
\[ x = \frac{1500}{2} \]
\[ x = 750 \]

### Final Answer
The number of units when marginal revenue equals zero is:
\[ x = 750 \]

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