Arrange in descending order:
39236457,41529366,41571245,392714512,39229366

Answer

To arrange the numbers in descending order, we will compare each number based on their value, starting from the largest. Here are the steps to solve the problem:

### Step 1: List the Numbers
We have the following numbers to arrange:
- 39236457
- 41529366
- 41571245
- 392714512
- 39229366

### Step 2: Identify the Largest Number
To find the largest number, we compare the first digits of each number:
- 39236457 (3)
- 41529366 (4)
- 41571245 (4)
- 392714512 (3)
- 39229366 (3)

The largest first digit is 4, which appears in 41529366 and 41571245. We will compare these two next.

### Step 3: Compare the Two Largest Numbers
Now we compare 41529366 and 41571245:
- 41529366 (4152...)
- 41571245 (4157...)

Since 4157 is greater than 4152, the larger number is 41571245.

### Step 4: List the Next Largest Number
Now we need to compare the remaining numbers:
- 39236457 (3)
- 392714512 (3)
- 39229366 (3)

All these numbers start with 3, so we need to compare them further.

### Step 5: Compare the Numbers Starting with 3
We will compare the numbers starting with 3:
- 39236457
- 392714512
- 39229366

Comparing the lengths:
- 392714512 has 9 digits, while the others have 8 digits, making it the largest.

Now we compare the remaining two:
- 39236457
- 39229366

Since 39236457 is greater than 39229366, we determine the order.

### Step 6: Final Arrangement
Now we can arrange all the numbers in descending order:
1. 41571245
2. 41529366
3. 392714512
4. 39236457
5. 39229366

### Final Answer
The numbers arranged in descending order are:
- 41571245
- 41529366
- 392714512
- 39236457
- 39229366

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