Solve:
`5+[6+2xx{3+(4-:2xx3-1)+7]-8]`

Answer

To solve the expression \( 5 + [6 + 2 \times \{3 + (4 \div 2 \times 3 - 1) + 7\} - 8] \), we will follow the BODMAS/BIDMAS rule, which stands for Brackets, Orders (powers and roots), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

### Step-by-Step Solution:

1. **Identify and Solve the Innermost Bracket:**
\[ (4 \div 2 \times 3 - 1) \]
- First, perform the division:
\[ 4 \div 2 = 2 \]
- Now substitute back into the expression:
\[ 2 \times 3 - 1 \]
- Next, perform the multiplication:
\[ 2 \times 3 = 6 \]
- Finally, perform the subtraction:
\[ 6 - 1 = 5 \]
- So, the innermost bracket simplifies to 5.

2. **Substitute Back into the Expression:**
\[ 5 + [6 + 2 \times \{3 + 5 + 7\} - 8] \]

3. **Simplify the Middle Bracket:**
\[ 3 + 5 + 7 \]
- Perform the addition:
\[ 3 + 5 = 8 \]
\[ 8 + 7 = 15 \]
- So, the middle bracket simplifies to 15.

4. **Substitute Back into the Expression:**
\[ 5 + [6 + 2 \times 15 - 8] \]

5. **Perform the Multiplication:**
\[ 2 \times 15 = 30 \]

6. **Substitute Back into the Expression:**
\[ 5 + [6 + 30 - 8] \]

7. **Simplify the Bracket:**
\[ 6 + 30 - 8 \]
- First, perform the addition:
\[ 6 + 30 = 36 \]
- Then perform the subtraction:
\[ 36 - 8 = 28 \]

8. **Final Addition:**
\[ 5 + 28 = 33 \]

### Final Answer:
The final answer is \( 33 \).

---